Transcript Ex 93, 5 (a) Add p (p – q), q (q – r) and r (r – p) Simplifying expressions p (p – q) = p × p – p × q = p2 – pq2 q (q – r) = q × q – q × r = q2 – qr r (r – p) = r × r – r × p = r2 – rp So, our answer is p2 q2 r2 – pq – qr – rp Ex 93, 5 (b) Add 2x (z – x – y) and 2y (z – y – x) Simplifying expressions 2x (z – x – y) = 2𝑥 ×And, conjuction, p /\ q, both variables have to be true Or, inclusive disjunction, p \/ q, only false if both variables are false Xor, Exclusive disjunction, p () q, p or q but not both The answer to this question would be pqr = 2 17 39= 58 In this question, p q r is a prime number Most of the prime number is an odd number If p q r all odd number, it wouldn't be possible to get 73 since odd x odd odd= odd odd = even Since 73 is an odd number, it is clear that one of the p q r needs to be an even number
If P Q And R Are Three Points On A Line And Q Lies Between P And R Then Prove That Pq Qr Pr Quora
